返回信息流我是新手，毕设在做基于opencv的双目视觉摄像机定标，其中有t=t1-R2*t2这个式子的运算，其中有一个矩阵和向量相乘的步骤，R2是个3*3矩阵，t2是个3*1的向量，他们之间的乘法怎么做啊?
我用这样有下面一个算式去做总是说输入变量形式不符合要求。
cvGEMM(rotation_matrix_invert.cvmat,
translation_vectors_right.get_col(i).cvmat,
-1,
NULL,
0,
translation_vectors_pair.get_col(i).cvmat,
0)
哪位达人帮帮我啊？我以前没接触过opencv
这是一条镜像帖。来源：北邮人论坛 / ml-dm / #4949同步于 2009/5/9
该镜像源已超过 30 天没有更新，可能在源站已被删除。
ML_DM机器人发帖
【求助】opencv中有关矩阵和向量进行相乘
thtyhust
2009/5/9镜像同步1 回复
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GEMM
Performs generalized matrix multiplication
void cvGEMM( const CvArr* src1, const CvArr* src2, double alpha,
const CvArr* src3, double beta, CvArr* dst, int tABC=0 );
#define cvMatMulAdd( src1, src2, src3, dst ) cvGEMM( src1, src2, 1, src3, 1, dst, 0 )
#define cvMatMul( src1, src2, dst ) cvMatMulAdd( src1, src2, 0, dst )
src1:: The first source array.src2:: The second source array.src3:: The third source array (shift). Can be NULL, if there is no shift.dst:: The destination array.tABC:: The operation flags that can be 0 or combination of the following values:
CV_GEMM_A_T - transpose src1
CV_GEMM_B_T - transpose src2
CV_GEMM_C_T - transpose src3
for example, CV_GEMM_A_T+CV_GEMM_C_T corresponds to
alpha*src1^T^*src2 + beta*src3^T^
The function cvGEMM performs generalized matrix multiplication:
dst = alpha*op(src1)*op(src2) + beta*op(src3), where op(X) is X or X^T^
All the matrices should have the same data type and the coordinated sizes. Real or complex floating-point matrices are supported