Re: c++作业题，求帝

change istream& operator>>(istream& is, const complex& complex_) to istream& operator>>(istream& is, complex& complex_) 【 在 sharonyue 的大作中提到: 】 : #include <iostream> : using namespace std; : class complex : ...................

【 在 tonyjansan 的大作中提到: 】 : change : istream& operator>>(istream& is, const complex& complex_) : to : ................... #include <iostream> using namespace std; class complex { private: double real_; double imaginary_; public: complex(); complex(double real,double imaginary_); ~complex(); complex operator+(const complex& complex_)const; complex operator-(const complex& complex_)const; complex operator*(const complex& complexa_,const complex& complexb_)const; friend complex operator*(double a,const complex& complex_); friend ostream& operator<<(ostream& os, const complex& complex_); friend istream& operator>>(istream& os, complex& complex_); }; complex::complex(){real_ = imaginary_ = 0;} complex::complex(double real,double imaginary) { real_ = real; imaginary_ = imaginary; } complex::~complex(){}; complex complex::operator+(const complex& complex_)const { complex sum; sum.real_ = real_ + complex_.real_; sum.imaginary_ = imaginary_ + complex_.imaginary_; return sum; } complex complex::operator-(const complex& complex_)const { complex sub; sub.real_= real_ - complex_.real_; sub.imaginary_ = imaginary_ - complex_.imaginary_; return sub; } complex operator*(double a,const complex& complex_)//友元不需要作用于操作符 { complex multiple; multiple.real_ = a * complex_.real_ ; multiple.imaginary_ = complex_.imaginary_ * a; return multiple; } complex complex::operator*(const complex& complexa_,const complex& complexb_)const { complex multiple; multiple.real_ = complexa_.real_ * complexb_.real_ ; multiple.imaginary_ = complexa_.imaginary_ * complexb_.imaginary_; return multiple; } ostream& operator<<(ostream& os, const complex& complex_) { os <<"(" << complex_.real_ <<"," << complex_.imaginary_ <<"i)" <<endl; return os; } istream& operator>>(istream& is, complex& newone) { is >> newone.real_; is >> newone.imaginary_; return is; } int main() { complex a (3.0,4.0); complex c; cout << "Enter a complex number(q to quit): \n"; while(cin >> c) { cout << "c is" << c <<'\n'; cout <<"a is " << a << '\n'; cout <<"a+c is" << a + c << '\n'; cout <<"2*c is" << 2 * c << '\n'; cout << "Enter a complex number(q to quit): \n"; } cout << "Done"; return 0; } 增加了一部分，报错，求女神中肯意见顺带跪舔。

complex complex::operator*(const complex& complex_)const { complex mul; mul.real_ = mul.real_ * complex_.real_ ; mul.imaginary_ = mul.imaginary_ * complex_.imaginary_; return mul; } 我改成这个之后，结果不对。但是编译成功

【 在 luotuo818 的大作中提到: 】 : 应该需要拷贝构造函数吧 为什么需要复制构造函数呢，我里面没有用new啊。

【 在 sharonyue 的大作中提到: 】 : 为什么需要复制构造函数呢，我里面没有用new啊。 我看错了，你想达到什么效果？实现两个复数相乘？

change complex operator*(const complex& complexa_,const complex& complexb_)const to friend complex operator*(const complex& complexa_,const complex& complexb_); or complex operator*(const complex& complex_)const; and are you sure that your complex multiplication is correct? 【 在 sharonyue 的大作中提到: 】 : : #include <iostream> : using namespace std; : ...................

【 在 tonyjansan 的大作中提到: 】 : change : complex operator*(const complex& complexa_,const complex& complexb_)const : to : ................... complex operator*(const complex& complex_)const; I have tried this but failed, see the last post, In mathematics this is wrong, while this doesnot matter, its just a excercise sweetie.

class complex { public: complex operator*(const complex& complex_)const; }; complex complex::operator*(const complex &complex_)const { complex mul; mul.real_ = this->real_ * complex_.real_; mul.imaginary_ = this->imaginary_ * complex_.imaginary_; return mul; } 你是想这样？ 【 在 sharonyue 的大作中提到: 】 : complex operator*(const complex& complex_)const; : Times New Roman

【 在 luotuo818 的大作中提到: 】 : 我看错了，你想达到什么效果？实现两个复数相乘？ 恩恩 类似吧 比如 3,4i * 2,2i = 6,8i