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c++ primer 9.28 编译通不过去啊？？？大侠们帮帮忙来。。

2010/11/4镜像同步9 回复

程序将一个list的所有元素赋值给一个vector。list存储的是char*指针，vector元素为string类型。程序如下： #include <iostream> #include<vector> #include<list> #include<string> using namespace std; int main() { char* sa[]={"mary","tom","gaby","bob"}; list<char*> slst(sa,sa+4); vector<string> svec; svec.assign(slst.begin(),slst.end()); cout<<"the list is:"<<endl; for(list<char*>::iterator iter1=slst.begin(); iter1!=slst.end();iter1++) { cout<<*iter1<<' '; } cout<<endl<<"the vector is:"<<endl; for(vector<string>::iterator iter2=svec.begin(); iter2!=svec.end();iter2++) { cout<<*iter2<<' '; } return 0; } 编译通不过去。。错误提示： --------------------Configuration: 9.28 - Win32 Debug-------------------- Compiling... 9.28.cpp C:\Documents and Settings\Administrator\9.28.cpp(12) : error C2664: 'void __thiscall std::vector<class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >,class std::allocator<class std::basic_string<char,struct std::ch ar_traits<char>,class std::allocator<char> > > >::assign(const class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> > *,const class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> > *) ' : cannot convert parameter 1 from 'class std::list<char *,class std::allocator<char *> >::iterator' to 'const class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> > *' No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called 执行 cl.exe 时出错. 9.28.exe - 1 error(s), 0 warning(s) 大侠们看看咋回事？？[ema27][ema27]

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