返回信息流(*二维平面随机数,r1 r2分别用随机数产生*)
circle [] := (
r1 = 1;
r2 = 1;
While[
(rr = Sqrt[r1^2 + r2^2]) > 1,
{
r1 = Random [Real , {-1, 1}];
r2 = Random [Real , {-1, 1}];
Return [{r1/rr, r2/rr}]
}
]
);
aa = Table[circle[], {i, 1, 100}];
ListPlot[aa, AspectRatio -> Automatic, PlotStyle -> PointSize[0.1]]
可是结果出不来阿...[em2]应该出来这样的图:\!\(\*
GraphicsBox[
{Hue[0.67, 0.6, 0.6], PointSize[0.01], PointBox[CompressedData["
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"]]},
Axes->True,
PlotRange->Automatic,
PlotRangeClipping->True]\)
这是一条镜像帖。来源:北邮人论坛 / math-model / #7144同步于 2010/11/24
该镜像源已超过 30 天没有更新,可能在源站已被删除。
MathModel机器人发帖
求帮助...一道小题,贺祖国留的
sunbird
2010/11/24镜像同步12 回复
订阅后,新回复会通过你的通知中心匿名送达。
9 条回复
我咋觉得这个程序很正确呢。。。
【 在 sunbird (广法星将) 的大作中提到: 】
: (*二维平面随机数,r1 r2分别用随机数产生*)
: circle [] := (
: r1 = 1;
: ...................
正确代码是
circle[] := Module[{r1 = 1, r2 = 1, rr = Sqrt[2]},
While[rr > 1,
{
r1 = Random[Real, {-1, 1}];
r2 = Random[Real, {-1, 1}];
rr = Sqrt[r1^2 + r2^2]
}];
Return[{r1, r2}]];
aa = Table[circle[], {i, 1, 1000}];
ListPlot[aa, AspectRatio -> Automatic]
这个结果ms有问题。。。
【 在 wanghaofei (Good Penetration) 的大作中提到: 】
: 正确代码是
: circle[] := Module[{r1 = 1, r2 = 1, rr = Sqrt[2]},
: While[rr > 1,
: ...................