返回信息流orthogonality with respect to time within each channel and with respect to frequency between channels is preserved by shaping the signals applied to each channel such that the integral of the mathematically transformed product of the squares of the shaping function applied to the individual channel and the channel transfer function and the integral of the transformed products of the shaping functions applied to adjacent channels and the square of the channel transfer function are each zero。
这句话太长了,看着直犯晕,请大牛指教。
这是一条镜像帖。来源:北邮人论坛 / communications / #11523同步于 2009/10/27
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Communications机器人发帖
请人帮我翻译一段话,关于正交性的
vos
2009/10/27镜像同步6 回复
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orthogonality with respect to time within each channel and with respect to frequency between channels is preserved by shaping the signals applied to each channel
每一个子信道中的时域正交性和子信道之间的频域正交性是靠信号的波形选择来达到的,(那这个波形选择的依据是啥捏?看到最后,)我们要让2种类型的积分(integral)都等于0.(那是哪两种积分捏?)
such that the integral of the mathematically transformed product of the squares of the shaping function applied to the individual channel and the channel transfer function and the integral of the transformed products of the shaping functions applied to adjacent channels and the square of the channel transfer function are each zero。
1. 第一个积分里面是个product,product的两项分别是
a) the squares of the shaping function applied to the individual channel
b) the channel transfer function
2. (很不凑巧,)第二个积分里面也是个product,product的两项分别是
a) the shaping functions applied to adjacent channels
b) the square of the channel transfer function
各信道中基于时域的正交性和信道间基于频域的正交性都是通过对各信道信号整形而保留下来的,为此应使得:每一个独立信道的整形函数的平方与当前信道传输函数的积的积分为零;相邻信道的整形函数与当前信道传输函数的平方的积的积分为零。
仅供参考
非常感谢您的回答,该解释让我豁然开朗,但是还有一点不明白,就是所谓的时域正交性和频域正交性是怎样定义的?我知道时域的正交性可以用两函数的积分等于零来定义,那频域正交呢?
时域正交了那么在频域中有什么表现?
【 在 ericyosho 的大作中提到: 】
: orthogonality with respect to time within each channel and with respect to frequency between channels is preserved by shaping the signals applied to each channel
: 每一个子信道中的时域正交性和子信道之间的频域正交性是靠信号的波形选择来达到的,(那这个波形选择的依据是啥捏?看到最后,)我们要让2种类型的积分(integral)都等于0.(那是哪两种积分捏?)
: such that the integral of the mathematically transformed product of the squares of the shaping function applied to the individual channel and the channel transfer function and the integral of the transformed products of the shaping functions applied to adjacent channels and the square of the channel transfer function are each zero。
: ...................
时域正交,频域就正交
【 在 vos 的大作中提到: 】
: 非常感谢您的回答,该解释让我豁然开朗,但是还有一点不明白,就是所谓的时域正交性和频域正交性是怎样定义的?我知道时域的正交性可以用两函数的积分等于零来定义,那频域正交呢?
: 时域正交了那么在频域中有什么表现?
其实我也是非常的不理解,我所知道的跟你差不多。为什么出来那么多平方之类的,不太明白。感觉好像是在算功率上面的正交?
【 在 vos 的大作中提到: 】
: 非常感谢您的回答,该解释让我豁然开朗,但是还有一点不明白,就是所谓的时域正交性和频域正交性是怎样定义的?我知道时域的正交性可以用两函数的积分等于零来定义,那频域正交呢?
: 时域正交了那么在频域中有什么表现?